Dim ... AS ... New

Syntax

dim args as classname1 = new classname2

Arguments

classname1: The new class type being created.
classname1: The new class type being assigned. In most situations, classname1 and classname2 will be the same.

Description

Discussion

If you have a class type, such as SQL::Arguments, and you say dim args as new SQL::Arguments = new SQL::Arguments, then whatever was there to begin with will be overwritten with the brand new definition of SQL::Arguments.

dim args as SQL::Arguments
args.set("MyArg","MyArgValue")

 new SQL::Arguments()

In some situations, the class of the variable you create is different from the assigned class. For example, in the code below, a variable named Stream is initially defined as a System::IO::Stream type. Later in the example, the Stream variable is assigned a new System::IO::MemoryStream object. The System::IO::MemoryStream is a type of System::IO::Stream class. Both classes are found in the .NET framework, which can be called into using Xbasic:

dim Stream as System::IO::Stream = null_value()
dim ContentType as C
dim Length as N
dim Buffer as B
dim CallResult as CallResult
dim Container as A5Storage::DataContainer = null_value()

Stream = new System::IO::MemoryStream()
CallResult = A5Storage::DataContainer::Open(Container, "Provider='Disk';Container='c:\A5Webroot';")
if CallResult.Success
    if Container.WriteItemToStream(Stream, Length, ContentType, "Speak.a5w")
        Stream.Seek(0, System::IO::SeekOrigin::Begin)

        dim Reader as System::IO::BinaryReader = new System::IO::BinaryReader(Stream)
        Buffer = Reader.ReadBytes(Length)
        Stream.close()
    else
        CallResult = Container.CallResult
    end if
end if

if CallResult.Success
    showvar("Type: " + ContentType + crlf() + "Length: " + Length + crlf(2) + buffer, "Success")
else
    showvar(CallResult.Text, "Error")
end if